EXPECTED PERFORMANCE, EXAMPLES  Click here to print this document

Example 1, SLAB (Hot mtrl, > curie temp)
In accordance with the specification,
Maximum allowed surface structure,
PFp-p: GK / 40
SUPPOSE THAT / DEMANDS  
Maximum allowed surface structure,
consequently, GK / 40 = 1,00 thus,
PFp-p: 1,00 mm
GK: 40
CALCULATION
(function of PFp-p), in accordance with the specification,
Minimum detectable crack depth, DJspr: GK / 50 = 40 / 50 = 0,8 mm
Minimum detectable sliver depth, DJsl: < GK / 80 = 40 / 80 =
< 0,5 mm
Minimum detectable hole diam, Dh: < GK / 12 = 40 / 12 = < 3,3 mm
Minimum detectable crack length, Lspr: GK / 1,5 = 40 / 1,5 = 27 mm
Maximum allowed lift-off, incl shield LO: GK / 2 = 40 / 2 = 20 mm


Example 2, SLAB (Hot mtrl, > curie temp)
In accordance with the specification,
Maximum allowed surface structure,
PFp-p: GK / 40
SUPPOSE THAT / DEMANDS  
Maximum allowed surface structure,
consequently, GK / 40 = 0,75 thus,
PFp-p: 0,75 mm
GK: 30
CALCULATION
(function of PFp-p), in accordance with the specification,
Minimum detectable crack depth, DJspr: GK / 50 = 30 / 50 = 0,6 mm
Minimum detectable sliver depth, DJsl: < GK / 80 = 30 / 80 =
< 0,4 mm
Minimum detectable hole diam, Dh: < GK / 12 = 30 / 12 = < 2,5 mm
Minimum detectable crack length Lspr: GK / 1,5 = 30 / 1,5 = 20 mm
Maximum allowed lift-off, incl shield LO: GK / 2 = 30 / 2 = 15 mm


Example 3, BILLET (Hot mtrl, > curie temp)
In accordance with the specification,
Maximum allowed surface structure,
PFp-p: GK / 40
SUPPOSE THAT / DEMANDS  
Maximum allowed surface structure,
consequently, GK / 40 = 0,5 thus,
PFp-p: 0,5 mm
GK: 20
CALCULATION
(function of PFp-p), in accordance with the specification,
Minimum detectable crack depth, DJspr: GK / 50 = 20 / 50 = 0,40 mm
Minimum detectable sliver depth, DJsl: < GK / 80 = 20 / 80 =
< 0,25 mm
Minimum detectable hole diam, Dh: < GK / 12 = 20 / 12 = < 1,7 mm
Minimum detectable crack length Lspr: GK / 1,5 = 20 / 1,5 = 13,4 mm
Maximum allowed lift-off, incl shield LO: GK / 2 = 20 / 2 = 10 mm


Example 4, BILLET (Hot mtrl, > curie temp)
In accordance with the specification,
Maximum allowed surface structure,
PFp-p: GK / 40
SUPPOSE THAT / DEMANDS  
Maximum allowed surface structure,
consequently, GK / 40 = 0,3 thus,
PFp-p: 0,3 mm
GK: 12
CALCULATION
(function of PFp-p), in accordance with the specification,
Minimum detectable crack depth, DJspr: GK / 50 = 12 / 50 = 0,24 mm
Minimum detectable sliver depth, DJsl: < GK / 80 = 12 / 80 =
< 0,15 mm
Minimum detectable hole diam, Dh: < GK / 12 = 12 / 12 = < 1 mm
Minimum detectable crack length Lspr: GK / 1,5 = 12 / 1,5 = 8 mm
Maximum allowed lift-off, incl shield LO: GK / 2 = 12 / 2 = 6 mm


Example 5, BILLETS (Hot mtrl, > curie temp)
SUPPOSE THAT / DEMANDS  
Minimum detectable crack depth DJspr: GK / 50 = 0,50 mm
CALCULATION
(function of DJspr), in accordance with the specification,
Consequently, GK / 50 = 0,50 thus, GK: 25
Current penetration depth (optimum), DIH: GK / 25 = 25/25 = 1,0 mm
Carrier frequencies (function of DIH and ), RF: MHZ
Maximum allowed lift-off, incl shield
Shield + water = 4,5 mm
LOabs: GK / 2 = 25 / 2 = 12,5 mm
Maximum available lift-off, free air
Maximum bulges = 3 mm
LOair+: LO - 4,5 = 8 mm
Lift off, free space/air LOfree: 8 - 3 = 5 mm
Calculation in accordance with the specification,
Maximum allowed surface structure,
Ra PFp-p / 4 = 0,15
PFp-p: GK / 40 = 25 / 40 = 0,6 mm
Maximum allowed Ra, Ra: 0,15 mm
Suppose,
Casting speed Vc: 200 mm/s
Rated speed, sensor n: 3000 rpm
Number of sensor channels/coils N: 1
Consequently, S = 200 x 60 / (1 x 3000) , S: 4 mm
Calculation in accordance with the specification (S/N > 3),
Minimum detectable crack length, stat (V=0) Lspr: GK / 1,5 = 25 / 1,5 16,7 mm (0 m/s)
Minimum detectable crack length, dyn (V=0,2) Lspr-rot: Lspr + S 20,7 mm
(0,2 m/s)
Minimum detectable sliver depth, DJsl: < GK / 80 = 25 / 80 =
< 0,3 mm
Minimum detectable hole diam, Dh: < GK / 12 = 25 / 12 = < 2 mm


Example 6, FLAT MACHINED SURFACE (Hot and cold mtrl)
In accordance with the specification,
Maximum allowed surface structure,
PFp-p: GK / 40
SUPPOSE THAT / DEMANDS  
Maximum allowed surface structure,
consequently, GK / 40 = 0,15 thus,
PFp-p: 0,15 mm
GK: 6
CALCULATION
(function of PFp-p), in accordance with the specification,
Minimum detectable crack depth, DJspr: GK / 50 = 6 / 50 = 0,12 mm
Minimum detectable sliver depth, DJsl: < GK / 80 = 6 / 80 =
< 0,08 mm
Minimum detectable hole diam, Dh: < GK / 12 = 6 / 12 = < 0,50 mm
Minimum detectable crack length, Lspr: GK / 1,5 = 6/ 1,5 = 4 mm
Maximum allowed lift-off, incl shield LO: GK / 2 = 6 / 2 = 3 mm


Example 7, WIRE, ROD and BAR (Hot and cold mtrl)
In accordance with the specification,
Maximum allowed surface structure,
PFp-p: GK / 40
SUPPOSE THAT / DEMANDS  
Maximum allowed surface structure,
consequently, GK / 40 = 0,10 thus,
PFp-p: 0,10 mm
GK: 4
CALCULATION
(function of PFp-p), in accordance with the specification,
Minimum detectable crack depth, DJspr: GK / 50 = 4 / 50 = 0,08 mm
Minimum detectable sliver depth, DJsl: < GK / 80 = 4 / 80 =
< 0,05 mm
Minimum detectable hole diam, Dh: < GK / 12 = 4 / 12 = < 0,33 mm
Minimum detectable crack length, Lspr: GK / 1,5 = 4 / 1,5 = 2,7 mm
Maximum allowed lift-off, incl shield LO: GK / 2 = 4 / 2 = 2,0 mm


Example 8, WIRE, ROD and BAR (Hot and cold mtrl)
Rotating sensors for detection of longitudinal "Long" cracks.
SUPPOSE THAT / DEMANDS  
Minimum detectable crack depth DJspr: GK / 50 = 0,20 mm
CALCULATION
(function of DJspr), in accordance with the specification,
Consequently, GK / 50 = 0,20 thus, GK: 10
Current penetration depth (optimum), DIH: GK / 25 = 10/25 = 0,4 mm
Maximum allowed lift-off, incl shield
Shield + water = 2,0 mm
LOabs: GK / 2 = 10 / 2 = 5,0 mm
Maximum available lift-off, free air LOair+: LO - 2,0 = 5,0 - 2,0 =
3,0 mm
Radial variation, ovality etc DEVtot: +/- < 0,5 mm
Assumption, radial movement dLO: < 0,5 mm
Minimum lift-off free air (ought to be 1 mm) LOair-: LOair+ - (0,5+0,5) = 2,0 mm
Calculation in accordance with the specification,
Maximum allowed surface structure,
Ra PFp-p / 5 = 0,05
PFp-p: GK / 40 = 10 / 40 = 0,25 mm
Maximum allowed Ra, Ra: 0,05 mm
Suppose,
Rolling speed / rod speed V: 20 m/s
Rated speed, sensor n: 6000 rpm
Number of channels N: 2
Consequently, S = 20 × 60 / (2 x 6000) , S20: 100 mm
Calculation in accordance with the specification,
Minimum detectable crack length,
stat (V=0)
Lspr: GK / 1,5 = 10 / 1,5 7 mm
(0 m/s)
Minimum detectable crack length,
dyn (V=5)
Lspr-rot: Lspr + S5 32 mm (5 m/s)
Minimum detectable crack length,
dyn (V=10)
Lspr-rot: Lspr + S10 57 mm
(10 m/s)
Minimum detectable crack length,
dyn (V=20)
Lspr-rot: Lspr + S20 107 mm
(20 m/s)

NOTE: At worst, Lspr-rot 107 mm (20 m/s). For instance, 50% of cracks, with length 107/2 55 mm, will also be detected.